380. Insert Delete GetRandom O(1)
380. Insert Delete GetRandom O(1)
Design a data structure that supports all following operations in average O(1) time.
insert(val)
: Inserts an item val to the set if not already present.remove(val)
: Removes an item val from the set if present.getRandom
: Returns a random element from current set of elements. Each element must have the same probability of being returned.
Example:
// Init an empty set.
RandomizedSet randomSet = new RandomizedSet();
// Inserts 1 to the set. Returns true as 1 was inserted successfully.
randomSet.insert(1);
// Returns false as 2 does not exist in the set.
randomSet.remove(2);
// Inserts 2 to the set, returns true. Set now contains [1,2].
randomSet.insert(2);
// getRandom should return either 1 or 2 randomly.
randomSet.getRandom();
// Removes 1 from the set, returns true. Set now contains [2].
randomSet.remove(1);
// 2 was already in the set, so return false.
randomSet.insert(2);
// Since 2 is the only number in the set, getRandom always return 2.
randomSet.getRandom();
My Solutions:
题目要求在O(1)的时间内完成插入, 删除, 取随机元素。
用linked lilst保存元素可以在O(1)内完成插入和删除, 但是无法在O(1)随机元素。
用数组可以在O(1)内完成插入和随机, 但是删除无法在O(1)完成。
如果用另外一种删除方式, 即把要删除的元素与最后的元素交换位置, 而删除最后一个元素就可以在O(1)完成。这样的话需要一个hash表来记录元素在数组的位置, 这样才可以O(1)取到这个元素, 并移动到尾部。还需要注意的是在删除一个元素的时候与另外一个元素交换了位置, 所以在hash表中还需要将另外一个元素的位置更新。由于哈希表的新增/删除操作是O(1),而数组的随机访问操作开销也是O(1),因此满足题设要求
用hashmap和list同时储存value和index。Use hashmap<int, int> set for insert and getRandom to store value and index; Use list的自带index位置储存value,list.get(index)可以达到O(1) 的insert和getRandom
难点是如何让remove也是O(1) - Use list<int> for remove[O(1)]: Always add the element to the end of the list, so when you need to remove a value, swap last element with the want-to-delete element:
1. find the last elem;
2. set last element to be at index position;
3. put last element in index position
class RandomizedSet {
HashMap<Integer, Integer> set;
List<Integer> list;
/** Initialize your data structure here. */
public RandomizedSet() {
set = new HashMap<>();
list = new ArrayList<>();
}
/** Inserts a value to the set. Returns true if the set did not already contain the specified element. */
public boolean insert(int val) {
if (set.containsKey(val)) return false;
set.put(val, set.size()); //insert到最后一个位置
list.add(val);
return true;
}
/** Removes a value from the set. Returns true if the set contained the specified element. */
public boolean remove(int val) {
if (!set.containsKey(val)) return false;
int index = set.get(val);
//swap last element with the want-to-delete element
if (index != list.size() - 1) {
int last = list.get(list.size() - 1); //last element
list.set(index, last); // set last element to be at index position in list
set.put(last, index); // put last element in index position
}
set.remove(val);
list.remove(list.size() - 1);
return true;
}
/** Get a random element from the set. */
public int getRandom() {
Random r = new Random();
int index = r.nextInt(set.size());
return list.get(index);
}
}
/**
* Your RandomizedSet object will be instantiated and called as such:
* RandomizedSet obj = new RandomizedSet();
* boolean param_1 = obj.insert(val);
* boolean param_2 = obj.remove(val);
* int param_3 = obj.getRandom();
*/
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