720. Longest Word in Dictionary

720. Longest Word in Dictionary

Given a list of strings words representing an English Dictionary, find the longest word in words that can be built one character at a time by other words in words. If there is more than one possible answer, return the longest word with the smallest lexicographical order.If there is no answer, return the empty string.

Example 1:

Input: 
words = ["w","wo","wor","worl", "world"]
Output: "world"
Explanation: 
The word "world" can be built one character at a time by "w", "wo", "wor", and "worl".

Example 2:

Input: 
words = ["a", "banana", "app", "appl", "ap", "apply", "apple"]
Output: "apple"
Explanation: 
Both "apply" and "apple" can be built from other words in the dictionary. However, "apple" is lexicographically smaller than "apply".

Note:

All the strings in the input will only contain lowercase letters.

The length of words will be in the range [1, 1000].

The length of words[i] will be in the range [1, 30].

My Solutions:

class Solution {
    
    class TrieNode {
        public TrieNode[] children;
        public boolean end;
            
        public TrieNode() {
            this.children = new TrieNode[26];
        }
    }
    
    class Trie {
        
        public TrieNode root;
        
        public Trie() {
            this.root = new TrieNode();
            root.end = true;
        }
        
        public void insert(String s) {
            TrieNode node = root;
            for (char c : s.toCharArray()) {
                if (node.children[c - 'a'] == null) node.children[c - 'a'] = new TrieNode();
                node = node.children[c - 'a'];
            }
            node.end = true;
        }
        
        public boolean search(String s) {
            TrieNode node = root;
            for (char c : s.toCharArray()) {
            
            // !node.end 表示如果在单词中找不到一个字母，直接返回false
                    
                if (node.children[c - 'a'] == null || !node.end) return false;
                node = node.children[c - 'a'];
            }
            return true;
        }
    }
    
    public String longestWord(String[] words) {
        
        Trie t = new Trie();
        for (String word : words) t.insert(word);
        
        String res = "";
        for (String word : words) {
            if (word.length() >= res.length() && t.search(word)) {
                if (word.length() > res.length()) res = word;
                else res = word.compareTo(res) < 0 ? word : res;
            }
        }
        return res;
    }
}